# What is the expected mean number of sixes appearing in 100 dice rolls?

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3. ex : boardgame after 100 rolls of the die a 6 appears 23 times, at one time there are 3 6’s in a row. … the probability of rolling a 6 on a fair die is 1/6, so that we expect 100 × 1/6 = 16.7 ≈ 17 6’s to be rolled.

## What is the expected number of rolls to get a 6?

It’s just two sequential sets of rolls to get a single six. It’s expected that we’ll take, on average, six rolls to get the first six, then another six from that point to get the second six. The expected numer of rolls to get to two sixes is 12.

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## What is the expected number of rolls of a 6 sided die until you roll a 6?

If you then take the expectation of that probability ( in other words how many times you expect to roll the die before you get a 6) is 1/p where p is the probability of rolling a 6. The probability of rolling a 6 will always be 1/6 since the experiment is independent. So the expected number of rolls will be 1/1/6=6.

## How do you calculate mean dice roll?

The mean is the type of average most people are used to. To find the mean for a set of numbers, add the numbers together and divide by the number of numbers in the set. For example, if you roll two dice thirteen times and get 9, 4, 7, 6, 11, 9, 10, 7, 9, 7, 11, 5, and 4, add the numbers to produce a sum of 99.

## What is the expected value of rolling a six sided die?

When you roll a fair die you have an equal chance of getting each of the six numbers 1 to 6. The expected value of your die roll, however, is 3.5.

## How do you get 6 on dice?

If you want to roll the 1 or 6, simply cover the numbers that are on opposite sides and bowl away. However, be wary that there is always a chance the dice will land on its side, especially if you’re not accustomed to this rolling technique.

## What is the expected number of rolls of a fair d6 6 sided dice until all 6 faces have appeared at least once?

The Expected Value

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6/6 + 6/5 + 6/4 + 6/3 + 6/2 + 6/1 = 14.7 rolls. When I told my son that “you should expect to roll the die 14.7 times before all six faces appear,” he was unimpressed.

## What is the expected number of times he rolls a 5 followed by a 6?

But the problem I solved did not have the answer as 42, the answer for the expected value to roll a 5 followed immediately by a 6 was 36.

## What is the expected value of the number 6 being rolled once in two rolls of a die?

A quantity equal to the average result of an experiment after a large number of trials. For example, if a fair 6-sided die is rolled, the expected value of the number rolled is 3.5.

## What is the expected number of throws including the last one which gives a 6?

… an average of 1.5 throws to see a 6.

## How do you compute an expected number?

The basic expected value formula is the probability of an event multiplied by the amount of times the event happens: (P(x) * n). The formula changes slightly according to what kinds of events are happening.

## How do u find the mean?

The mean, or average, is calculated by adding up the scores and dividing the total by the number of scores.

## What is the mean of all number in a dice?

Answered 4 years ago · Author has 225 answers and 294.3K answer views. Each face has equal probability of coming up, so if the dice is rolled a large number of times, theoretically the mean value should be the mean of all the possible scores, since each score appears same number of times. So 1+2+3+4+5+6=21. 21/6= 3.5.

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## What is the expected number of dots appearing on two dice?

1 + 2 + 3 + 4 + 5 + 6 = 21 dots on one die. So 2 dice will have 42 dots.

## What is expected sum?

The expected value of the sum of several random variables is equal to the sum of their expectations, e.g., E[X+Y] = E[X]+ E[Y] . On the other hand, the expected value of the product of two random variables is not necessarily the product of the expected values.

## What is the expected value of rolling a dice if you could roll twice?

Suppose you have only two rolls of dice. then your best strategy would be to take the first roll if its outcome is more than its expected value (ie 3.5) and to roll again if it is less. Hence the expected payoff of the game rolling twice is: 16(6+5+4)+123.5=4.25.